3.14^2 ~ 9.8
Saturday, January 27, 2007
Interesting Coincidence
The square root of the gravitational acceleration on the surface of the earth roughly equals to pi:
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3 comments:
i thought that only engineers are supposed to approximate!!
No, I realised that when the numerical answer in one of my questions looked like pi/2 and when I got root(g)/2, and I thought I was wrong...
Turns out that pi/2 ~ root(g)/2 to 3 significant figures!
No, there's some spooky deep connection between the radius of the earth and the ratio of the radius of a circle to the circumfrence.
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